24VDC Power Supply Sizer

This free 24VDC power supply sizer adds up the DC loads in your control panel and tells you what size DIN-rail supply to buy. Enter your loads in six categories — industrial PC, PLC, HMI, network switch, I/O and sensors, and everything else — set your design headroom, and it sums the panel, applies the headroom, works out the required current, and rounds up to a standard DIN-rail wattage. It's for controls and automation engineers laying out a new panel, checking whether an added device overloads an existing supply, or replacing a failed unit with confidence instead of guesswork. No account, no spreadsheet — the method and its limits are shown below.

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Add common panel loads and size a practical DIN-rail power supply.

Sums entered DC loads and applies your design headroom. Recommended standard wattage is rounded up to a common DIN-rail size. Verify startup/inrush current, redundancy, ambient derating, NEC/UL requirements, and manufacturer curves separately.

The formula

There is no exotic maths here — sizing a DC supply is a disciplined addition problem. The mistakes happen in what gets left out, which is why the method has three steps instead of one:

Connected load (six category fields, all in watts)
  P_load = P_IPC + P_PLC + P_HMI + P_switch + P_IO + P_other

Design load
  P_design = P_load × (1 + H ÷ 100)
  I_req    = P_design ÷ V          amps (V defaults to 24 VDC)

Recommendation
  P_supply = first standard size ≥ P_design, from
             30, 60, 75, 100, 120, 150, 240, 320, 480, 600, 960, 1200 W
             (above 1200 W: the next 240 W multiple)
  Loading  = P_load ÷ P_supply × 100%
VariableMeaningWhere it comes from
P_IPC … P_otherThe six load-category fields, in watts: Industrial PC, PLC / controller, HMI / panel PC, Ethernet switch, I/O + sensors, Other 24V loadsYour panel design, summed per category from device datasheets or nameplates; convert a current draw to watts with P = I × V
P_loadConnected continuous load — the total steady-state draw on the supplyThe sum this calculator builds
HDesign headroom, in percent (0–200)Your judgement; 20–30% is a common planning range (see the glossary)
VBus voltage, in volts DC (default 24)Your panel's DC bus
P_designDesign load — the capacity you actually need to buy forP_load with headroom applied
I_reqRequired DC currentP_design ÷ V
P_supplyThe recommended standard PSU sizeThe first ladder size at or above P_design (ladder verified in source)

Why watts first, and why the round-up: panel loads are documented in watts on most datasheets, so the categories are entered in watts, and the calculator derives the current from the design load at your bus voltage. The headroom step is not padding — datasheets quote a mix of typical and maximum draws, panels accumulate small loads nobody listed, and a supply that runs near full load runs hot and ages fast. The round-up step exists because DIN-rail supplies come in standard sizes: a 200 W design load doesn't buy a 200 W supply, it buys the next size up (240 W), and the difference between the two numbers is thermal margin and expansion room, not waste.

One side effect worth knowing: the supply turns a few percent of everything it delivers into heat inside your cabinet. At around 90% efficiency, delivering the 160 W in the worked example below means roughly 18 W of heat from the supply alone — feed that into the Enclosure Cooling calculator when you check cabinet temperature rise.

What each input means

Every field below is exactly as it appears in the live calculator (labels and defaults verified in source). All loads are entered as one watt figure per category — if a device is documented in amps, convert it first: watts = amps × bus voltage.

InputUnitDefaultWhat breaks if you get it wrong
Industrial PC (W)W45The IPC is usually the single biggest load in the panel. Leaving it at the default when your unit is larger — or zeroing it when the IPC is fed from this same rail — moves the result by more than every other field combined
PLC / controller (W)W20Enter the CPU plus anything powered through the controller's own supply terminals. Using the CPU's bare figure when expansion modules hang off it understates this category
HMI / panel PC (W)W25Panel PCs vary widely (10–40 W+). A guess here is also the inrush risk: HMIs draw a switch-on surge this steady-state sum doesn't model
Ethernet switch (W)W15The classic forgotten load — managed switches, media converters and gateways all sit on this rail. Leave it out and the design load is understated before headroom even applies
I/O + sensors (W)W35Sum everything the rail feeds in the field: I/O modules, sensor loops, relay and contactor coils, solenoid valves. Field devices powered from the same rail are the classic omission in panel sizing
Other 24V loads (W)W20The catch-all for whatever doesn't fit the five categories — stack lights, small drives' control power, the "temporary" commissioning device that never left. If it draws from this supply, it belongs in the sum
Design headroom (%)% (0–200)250% means the design load equals today's load, with nothing left for the device added in year two or for datasheet optimism. Very high values push the recommendation up the size ladder, adding cost, panel space, and cabinet heat for margin you'll never use. 20–30% is a common planning range
Bus voltage (VDC)V24The required current is design load ÷ voltage, so this field decides the amp figure. It also anchors the verdict text. Setting it to anything other than your actual bus voltage makes the current output meaningless, even though the watt math still works

Worked example

Scenario: a mid-size machine control panel — an industrial PC, PLC, panel HMI, managed switch, the I/O and field devices, and the usual extras, all fed from a single 24VDC DIN-rail supply. The inputs below are the calculator's own starting values, so you can reproduce this example exactly by opening the calculator and pressing "Size power supply" without changing anything.

Inputs (the calculator's defaults):

  • Industrial PC: 45 W
  • PLC / controller: 20 W
  • HMI / panel PC: 25 W
  • Ethernet switch: 15 W
  • I/O + sensors: 35 W
  • Other 24V loads: 20 W
  • Design headroom: 25%
  • Bus voltage: 24 VDC

Step by step:

  1. Connected load: 45 + 20 + 25 + 15 + 35 + 20 = 160 W
  2. Apply headroom: 160 × 1.25 = 200 W design load
  3. Required current: 200 ÷ 24 = ≈ 8.33 A
  4. Round up the ladder (30, 60, 75, 100, 120, 150, 240, …): 200 W sits above the 150 W size, so the recommendation is the next standard size — 240 W (240 ÷ 24 = 10 A)
  5. Loading on the recommended unit: 160 ÷ 240 = 66.7% of its rating in steady state

The calculator's verdict for these inputs reads: "Select at least a 240 W supply at 24 VDC, then verify inrush, redundancy, temperature derating, and future expansion."

What the example shows: headroom mostly decides which step of the ladder you land on. Same panel with 0% headroom: the design load is 160 W, still above 150 W, so the pick is still 240 W — but now the supply runs at 66.7% with nothing reserved for the next device. Take a lighter panel with a 100 W connected load and the same 25% headroom: the design load is 125 W, and the pick falls to the 150 W step. And at the small end, a 52 W panel load with 25% headroom is a 65 W design load, which lands on the 75 W size — not a 120 W unit. Each ladder step you land on decides how hard the supply works for its whole life: a unit cruising near two-thirds load in a warm cabinet is far more likely to stay inside its derating curve than one pinned near full rating (see Common Mistakes).

What the result tells you

The result panel shows four figures (labels as displayed by the live calculator), followed by a one-line verdict:

  • Connected continuous load — the sum of the six category fields, in watts: your panel's steady-state draw before any margin. This is the number to compare against an existing supply's rating when you're checking whether an added device will overload it.
  • Design load with headroom — the connected load with your headroom applied: the capacity you actually need to buy for. If this number sits close to a ladder boundary (say 148 W against the 150 W step), small load changes flip the recommendation — re-check it whenever the design changes.
  • Required DC current — design load ÷ bus voltage, in amps. Use it to check the supply's current rating and your wire and protection sizing at the actual bus voltage.
  • Recommended standard PSU — the first ladder size at or above the design load, shown in watts and amps (e.g. "240 W / 10 A"). The gap between this and your connected load is deliberate: thermal margin plus room to grow.
  • The verdict line — restates the pick as a purchase instruction: "Select at least a {size} W supply at {voltage} VDC, then verify inrush, redundancy, temperature derating, and future expansion." Those four verifications are exactly what the result does not cover: whether the supply survives switch-on (inrush), a hot cabinet (derating), or a redundancy scheme sits outside a load sum, and the calculator's own assumptions add NEC/UL requirements and manufacturer curves to that list. Check them against the chosen unit's datasheet before you order.

Common mistakes

  1. Sizing to the exact load. Set headroom to 0% and the design load is just today's connected load — the calculator will happily recommend a unit the panel already fills, in a sealed cabinet, forever. Supplies run at or near full rating run hot and fail early, and the first added sensor or relay has nowhere to go. Headroom is the cheapest reliability in the panel.
  2. Forgetting inrush. The load sum is steady-state. At switch-on, an HMI, capacitive sensor loads, and a bank of inputs can draw several times their running current for a few milliseconds; a supply sized exactly to the sum can hiccup or trip on its overload characteristic at every power-up. The calculator deliberately excludes inrush — check the chosen unit's overload behaviour against your loads' startup draw.
  3. Ignoring ambient derating. A supply's nameplate watts apply up to a stated ambient temperature; above it, the manufacturer derates output — in a 55–60 °C cabinet the same unit may only be good for a fraction of its label. Read the derating curve for your cabinet temperature, and note the interplay with Mistake 1: a supply running at two-thirds load has derating room, one pinned near full rating doesn't.
  4. Leaving loads off the list. The forgotten ones are consistent: field sensors powered from the panel rail, the Ethernet switch, coil loads for contactors and solenoid valves, the "temporary" device from commissioning that never left. If it draws from this supply, it belongs in the sum — walk the panel and the field, don't size from the PLC configuration alone.
  5. Treating watts as the whole job. A correctly sized supply can still deliver a bad installation: long, thin 24 VDC runs drop voltage, so the far end of the panel sees well under 24 V even though the supply is loafing. Sizing the supply and sizing the wire are separate checks (a voltage drop calculator is on this site's roadmap).

FAQ

How do I size a 24VDC power supply for a PLC panel?

Total up every DC load the supply will feed, grouped the way this calculator does: industrial PC, PLC/controller, HMI, network switch, I/O and sensors, and any other 24 V loads — all in watts (convert a current draw to watts first: amps × volts). Then apply a design headroom, typically 20–30%, and choose the next standard DIN-rail size at or above that figure. That is exactly the calculator's method: sum the six categories, apply headroom, round up the size ladder.

How much headroom should I leave on a 24VDC power supply?

20–30% above the summed load is a common planning range. It covers datasheet optimism, loads you forgot, and the devices that get added in year two. Go higher — around 50% — when expansion is planned or the cabinet runs hot, because a supply that lives at 40–60% load runs cooler and lasts longer than one pinned at 95%.

Why did the calculator recommend a 240 W supply when my design load is only 200 W?

Because DIN-rail supplies come in standard sizes, and it is the design load — connected load plus headroom — that gets rounded up, not the raw load. The standard ladder runs 30, 60, 75, 100, 120, 150, 240 W and beyond; a 200 W design load sits above the 150 W step, so the next size up is 240 W (10 A at 24 V). The apparent oversizing is mostly thermal margin and expansion room: the connected load in that example runs the recommended unit at about two-thirds of its rating.

How many amps is a 240 W, 24V power supply?

10 amps — watts divided by volts: 240 ÷ 24 = 10. The standard steps this calculator uses work out at 24 V as: 30 W = 1.25 A, 60 W = 2.5 A, 75 W = 3.13 A, 100 W = 4.17 A, 120 W = 5 A, 150 W = 6.25 A, 240 W = 10 A, 480 W = 20 A. If a device on your list is documented in amps instead of watts, multiply by the bus voltage (24) to get watts before adding it to a category.

Does this calculator account for inrush current, redundancy, or temperature derating?

No — deliberately. It sizes the steady-state load and applies your headroom. Startup and inrush current (an HMI or a bank of capacitive loads can draw several times its running current at switch-on), redundant supply arrangements, ambient-temperature derating, and NEC/UL requirements all sit outside a load sum and must be checked against the chosen manufacturer's data separately — the same caveat the calculator itself shows.

Should the PLC and field devices share one power supply?

They can, and small panels often do. Many engineers split them anyway: one supply for the PLC, HMI, and control side, a second for field outputs and sensors. A short on a field device then can't drag down the supply feeding the controller, and troubleshooting is simpler. If you split, run this calculator once per supply with only that supply's loads.

Related tools and reading

Sizing the rest of the panel?

The free Controls Toolkit includes editable Excel workbooks and printable PDF worksheets for system sizing, network planning, and commissioning — starting with Industrial PC sizing and EtherCAT timing budgets, with more resources on the way. Free by email signup.